TSTP Solution File: NUM666^1 by cocATP---0.2.0
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%------------------------------------------------------------------------------
% File : cocATP---0.2.0
% Problem : NUM666^1 : TPTP v7.0.0. Released v3.7.0.
% Transfm : none
% Format : tptp:raw
% Command : python CASC.py /export/starexec/sandbox/benchmark/theBenchmark.p
% Computer : n186.star.cs.uiowa.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2609 0 2.40GHz
% Memory : 32218.625MB
% OS : Linux 3.10.0-693.2.2.el7.x86_64
% CPULimit : 300s
% DateTime : Mon Jan 8 13:11:22 EST 2018
% Result : Theorem 0.35s
% Output : Proof 0.35s
% Verified :
% SZS Type : None (Parsing solution fails)
% Syntax : Number of formulae : 0
% Comments :
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%----WARNING: Could not form TPTP format derivation
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%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.03 % Problem : NUM666^1 : TPTP v7.0.0. Released v3.7.0.
% 0.00/0.04 % Command : python CASC.py /export/starexec/sandbox/benchmark/theBenchmark.p
% 0.03/0.24 % Computer : n186.star.cs.uiowa.edu
% 0.03/0.24 % Model : x86_64 x86_64
% 0.03/0.24 % CPU : Intel(R) Xeon(R) CPU E5-2609 0 @ 2.40GHz
% 0.03/0.24 % Memory : 32218.625MB
% 0.03/0.24 % OS : Linux 3.10.0-693.2.2.el7.x86_64
% 0.03/0.24 % CPULimit : 300
% 0.03/0.24 % DateTime : Fri Jan 5 12:13:07 CST 2018
% 0.03/0.24 % CPUTime :
% 0.03/0.25 Python 2.7.13
% 0.35/0.60 Using paths ['/home/cristobal/cocATP/CASC/TPTP/', '/export/starexec/sandbox/benchmark/', '/export/starexec/sandbox/benchmark/']
% 0.35/0.60 FOF formula (<kernel.Constant object at 0x2ac0f8a89ea8>, <kernel.Type object at 0x2ac0f8a89b90>) of role type named nat_type
% 0.35/0.60 Using role type
% 0.35/0.60 Declaring nat:Type
% 0.35/0.60 FOF formula (<kernel.Constant object at 0x2ac0f8730998>, <kernel.Constant object at 0x2ac0f8a89f80>) of role type named x
% 0.35/0.60 Using role type
% 0.35/0.60 Declaring x:nat
% 0.35/0.60 FOF formula (<kernel.Constant object at 0x2ac0f8730998>, <kernel.Constant object at 0x2ac0f8a89f80>) of role type named y
% 0.35/0.60 Using role type
% 0.35/0.60 Declaring y:nat
% 0.35/0.60 FOF formula (<kernel.Constant object at 0x2ac0f8a89ea8>, <kernel.Constant object at 0x2ac0f8a89f80>) of role type named z
% 0.35/0.60 Using role type
% 0.35/0.60 Declaring z:nat
% 0.35/0.60 FOF formula (<kernel.Constant object at 0x2ac0f8a89f38>, <kernel.DependentProduct object at 0x2ac0f8a89d40>) of role type named some
% 0.35/0.60 Using role type
% 0.35/0.60 Declaring some:((nat->Prop)->Prop)
% 0.35/0.60 FOF formula (<kernel.Constant object at 0x2ac0f8a89b48>, <kernel.DependentProduct object at 0x2ac0f8a89b00>) of role type named diffprop
% 0.35/0.60 Using role type
% 0.35/0.60 Declaring diffprop:(nat->(nat->(nat->Prop)))
% 0.35/0.60 FOF formula (some (fun (Xu:nat)=> (((diffprop x) y) Xu))) of role axiom named m
% 0.35/0.60 A new axiom: (some (fun (Xu:nat)=> (((diffprop x) y) Xu)))
% 0.35/0.60 FOF formula (<kernel.Constant object at 0x2ac0f8a89b48>, <kernel.DependentProduct object at 0x2ac0f8a89b00>) of role type named moreis
% 0.35/0.60 Using role type
% 0.35/0.60 Declaring moreis:(nat->(nat->Prop))
% 0.35/0.60 FOF formula ((moreis y) z) of role axiom named n
% 0.35/0.60 A new axiom: ((moreis y) z)
% 0.35/0.60 FOF formula (<kernel.Constant object at 0x2ac0f8a89830>, <kernel.DependentProduct object at 0x2ac0f8a893f8>) of role type named lessis
% 0.35/0.60 Using role type
% 0.35/0.60 Declaring lessis:(nat->(nat->Prop))
% 0.35/0.60 FOF formula (forall (Xx:nat) (Xy:nat) (Xz:nat), (((lessis Xx) Xy)->((some (fun (Xv:nat)=> (((diffprop Xz) Xy) Xv)))->(some (fun (Xv:nat)=> (((diffprop Xz) Xx) Xv)))))) of role axiom named satz16a
% 0.35/0.60 A new axiom: (forall (Xx:nat) (Xy:nat) (Xz:nat), (((lessis Xx) Xy)->((some (fun (Xv:nat)=> (((diffprop Xz) Xy) Xv)))->(some (fun (Xv:nat)=> (((diffprop Xz) Xx) Xv))))))
% 0.35/0.60 FOF formula (forall (Xx:nat) (Xy:nat), (((moreis Xx) Xy)->((lessis Xy) Xx))) of role axiom named satz13
% 0.35/0.60 A new axiom: (forall (Xx:nat) (Xy:nat), (((moreis Xx) Xy)->((lessis Xy) Xx)))
% 0.35/0.60 FOF formula (some (fun (Xu:nat)=> (((diffprop x) z) Xu))) of role conjecture named satz16d
% 0.35/0.60 Conjecture to prove = (some (fun (Xu:nat)=> (((diffprop x) z) Xu))):Prop
% 0.35/0.60 We need to prove ['(some (fun (Xu:nat)=> (((diffprop x) z) Xu)))']
% 0.35/0.60 Parameter nat:Type.
% 0.35/0.60 Parameter x:nat.
% 0.35/0.60 Parameter y:nat.
% 0.35/0.60 Parameter z:nat.
% 0.35/0.60 Parameter some:((nat->Prop)->Prop).
% 0.35/0.60 Parameter diffprop:(nat->(nat->(nat->Prop))).
% 0.35/0.60 Axiom m:(some (fun (Xu:nat)=> (((diffprop x) y) Xu))).
% 0.35/0.60 Parameter moreis:(nat->(nat->Prop)).
% 0.35/0.60 Axiom n:((moreis y) z).
% 0.35/0.60 Parameter lessis:(nat->(nat->Prop)).
% 0.35/0.60 Axiom satz16a:(forall (Xx:nat) (Xy:nat) (Xz:nat), (((lessis Xx) Xy)->((some (fun (Xv:nat)=> (((diffprop Xz) Xy) Xv)))->(some (fun (Xv:nat)=> (((diffprop Xz) Xx) Xv)))))).
% 0.35/0.60 Axiom satz13:(forall (Xx:nat) (Xy:nat), (((moreis Xx) Xy)->((lessis Xy) Xx))).
% 0.35/0.60 Trying to prove (some (fun (Xu:nat)=> (((diffprop x) z) Xu)))
% 0.35/0.60 Found m:(some (fun (Xu:nat)=> (((diffprop x) y) Xu)))
% 0.35/0.60 Found m as proof of (some (fun (Xv:nat)=> (((diffprop x) y) Xv)))
% 0.35/0.60 Found n:((moreis y) z)
% 0.35/0.60 Found n as proof of ((moreis y) z)
% 0.35/0.60 Found (satz1300 n) as proof of ((lessis z) y)
% 0.35/0.60 Found ((satz130 z) n) as proof of ((lessis z) y)
% 0.35/0.60 Found (((satz13 y) z) n) as proof of ((lessis z) y)
% 0.35/0.60 Found (((satz13 y) z) n) as proof of ((lessis z) y)
% 0.35/0.60 Found ((satz16a000 (((satz13 y) z) n)) m) as proof of (some (fun (Xu:nat)=> (((diffprop x) z) Xu)))
% 0.35/0.60 Found (((satz16a00 y) (((satz13 y) z) n)) m) as proof of (some (fun (Xu:nat)=> (((diffprop x) z) Xu)))
% 0.35/0.60 Found ((((fun (Xy:nat)=> ((satz16a0 Xy) x)) y) (((satz13 y) z) n)) m) as proof of (some (fun (Xu:nat)=> (((diffprop x) z) Xu)))
% 0.35/0.60 Found ((((fun (Xy:nat)=> (((satz16a z) Xy) x)) y) (((satz13 y) z) n)) m) as proof of (some (fun (Xu:nat)=> (((diffprop x) z) Xu)))
% 0.35/0.60 Found ((((fun (Xy:nat)=> (((satz16a z) Xy) x)) y) (((satz13 y) z) n)) m) as proof of (some (fun (Xu:nat)=> (((diffprop x) z) Xu)))
% 0.35/0.60 Got proof ((((fun (Xy:nat)=> (((satz16a z) Xy) x)) y) (((satz13 y) z) n)) m)
% 0.35/0.61 Time elapsed = 0.064590s
% 0.35/0.61 node=17 cost=387.000000 depth=9
% 0.35/0.61::::::::::::::::::::::
% 0.35/0.61 % SZS status Theorem for /export/starexec/sandbox/benchmark/theBenchmark.p
% 0.35/0.61 % SZS output start Proof for /export/starexec/sandbox/benchmark/theBenchmark.p
% 0.35/0.61 ((((fun (Xy:nat)=> (((satz16a z) Xy) x)) y) (((satz13 y) z) n)) m)
% 0.35/0.61 % SZS output end Proof for /export/starexec/sandbox/benchmark/theBenchmark.p
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